Leetcode / 199. Binary Tree Right Side View
Pick a programming language:
Here is the source code for the solution to this problem.
/**
* Definition for a binary tree node.
* public class TreeNode {
* int val;
* TreeNode left;
* TreeNode right;
* TreeNode() {}
* TreeNode(int val) { this.val = val; }
* TreeNode(int val, TreeNode left, TreeNode right) {
* this.val = val;
* this.left = left;
* this.right = right;
* }
* }
*/
class Solution {
public List<Integer> rightSideView(TreeNode root) {
Queue<TreeNode> queue = new LinkedList<>();
List<Integer> values = new LinkedList<>();
if (root == null) {
return values;
}
queue.offer(root);
while (!queue.isEmpty()) {
values.add(queue.peek().val);
int size = queue.size();
while (size > 0) {
TreeNode curr = queue.poll();
if (curr.right != null) {
queue.offer(curr.right);
}
if (curr.left != null) {
queue.offer(curr.left);
}
size--;
}
}
return values;
}
}
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