Leetcode / 257. Binary Tree Paths
Pick a programming language:
Here is the source code for the solution to this problem.
/**
* Definition for a binary tree node.
* public class TreeNode {
* int val;
* TreeNode left;
* TreeNode right;
* TreeNode() {}
* TreeNode(int val) { this.val = val; }
* TreeNode(int val, TreeNode left, TreeNode right) {
* this.val = val;
* this.left = left;
* this.right = right;
* }
* }
*/
class Solution {
private void traverse(TreeNode root, String pathSoFar, List<String> list) {
if (root == null) {
return;
}
if (pathSoFar.length() > 0) {
pathSoFar = pathSoFar + "->";
}
pathSoFar = pathSoFar + root.val;
if (root.left == null && root.right == null) {
// a leaf
list.add(pathSoFar);
}
traverse(root.left, pathSoFar, list);
traverse(root.right, pathSoFar, list);
}
public List<String> binaryTreePaths(TreeNode root) {
List<String> list = new LinkedList<String>();
traverse(root, "", list);
return list;
}
}
Did you like the lesson? 😆👍
Consider a donation to support our work: